Comments for Ajax Tutorial : Ajax Help and Tutorials http://www.ajaxtutorial.net Helping newbies learn AJAX with Tutorials Sat, 10 May 2008 02:04:25 +0000 http://wordpress.org/?v=2.0.7 Comment on Simple Ajax using Prototype. Part 1 by banjojim http://www.ajaxtutorial.net/index.php/2006/11/29/simple-ajax-using-prototype-part-1/#comment-201 Sun, 28 Jan 2007 00:36:17 +0000 http://www.ajaxtutorial.net/index.php/2006/11/29/simple-ajax-using-prototype-part-1/#comment-201 I'm running your example but the return value is the following: if(isset($_GET[�val�])) { echo �You entered: �.$_GET[�val�]; } It seems like PHP isn't parsing the script. I know PHP is working because php phpinfo() works fine. Any suggestions? I'm sure it's a PHP problem but I'm not sure how to continue. I’m running your example but the return value is the following:

if(isset($_GET[�val�])) { echo �You entered: �.$_GET[�val�]; }

It seems like PHP isn’t parsing the script. I know PHP is working because php phpinfo() works fine. Any suggestions? I’m sure it’s a PHP problem but I’m not sure how to continue.

]]> Comment on Simple Ajax using Prototype. Part 1 by Stuart http://www.ajaxtutorial.net/index.php/2006/11/29/simple-ajax-using-prototype-part-1/#comment-200 Wed, 24 Jan 2007 23:12:33 +0000 http://www.ajaxtutorial.net/index.php/2006/11/29/simple-ajax-using-prototype-part-1/#comment-200 beachbumdrums, I'm not to sure why you get this error. If possible can you run it with FF2 with the Firebug extension? this will give you a better indication of where exactly the error is coming from. Also, I do not know if this makes any difference, but try changing the ` (funny single quotes which wordpress generates) to proper single quotes. Sometime wordpress changes the code a little. Finally you could take out the F() function, and place: < input type="button" value="GO" onClick="ajaxRequest('parse.php', 'val='+document.getElementById('myval').value)" > Good luck. beachbumdrums,

I’m not to sure why you get this error. If possible can you run it with FF2 with the Firebug extension? this will give you a better indication of where exactly the error is coming from.

Also, I do not know if this makes any difference, but try changing the ` (funny single quotes which wordpress generates) to proper single quotes. Sometime wordpress changes the code a little.

Finally you could take out the F() function, and place:
< input type="button" value="GO" onClick="ajaxRequest('parse.php', 'val='+document.getElementById('myval').value)" >

Good luck.

]]> Comment on Simple Ajax using Prototype. Part 1 by beachbumdrums http://www.ajaxtutorial.net/index.php/2006/11/29/simple-ajax-using-prototype-part-1/#comment-198 Wed, 24 Jan 2007 20:05:55 +0000 http://www.ajaxtutorial.net/index.php/2006/11/29/simple-ajax-using-prototype-part-1/#comment-198 Please help... I applaud this tutorial. I am a php coder who needs a simple intro to ajax like this in order to build upon. However, I get an error message that I can not resolve. "object expected" on the input button line. How do I resolve this? Thanks in advance! I look forward to more tutorials. Please help…

I applaud this tutorial. I am a php coder who needs a simple intro to ajax like this in order to build upon.

However, I get an error message that I can not resolve. “object expected” on the input button line. How do I resolve this?

Thanks in advance! I look forward to more tutorials.

]]> Comment on Simple Ajax using Prototype. Part 2 by Stuart http://www.ajaxtutorial.net/index.php/2006/11/30/simple-ajax-using-prototype-part-2/#comment-139 Mon, 04 Dec 2006 22:47:31 +0000 http://www.ajaxtutorial.net/index.php/2006/11/30/simple-ajax-using-prototype-part-2/#comment-139 From what I understand, ajax.Updater is used to request updated info from a Server Script, i.e. you do not send a request, you only receive a reply. But ajax.Request is used to send values to a Server Script and also receives a reply (if required). It really depends on what you want to do. From what I understand, ajax.Updater is used to request updated info from a Server Script, i.e. you do not send a request, you only receive a reply. But ajax.Request is used to send values to a Server Script and also receives a reply (if required). It really depends on what you want to do.

]]> Comment on Simple Ajax using Prototype. Part 2 by tom http://www.ajaxtutorial.net/index.php/2006/11/30/simple-ajax-using-prototype-part-2/#comment-138 Mon, 04 Dec 2006 11:24:32 +0000 http://www.ajaxtutorial.net/index.php/2006/11/30/simple-ajax-using-prototype-part-2/#comment-138 Sorry, but I don't really get the difference between ajaxUpdater and ajaxRequest. What can be done with ajaxUpdater which can't be done with ajaxRequest? I've just used your ajaxRequest tutorial to create my first bit of ajax, thanks a lot for the help, very very handy. I built the ajax part in less than 20 min... without that tutorial, it would have probably taken me several hours. Sorry, but I don’t really get the difference between ajaxUpdater and ajaxRequest. What can be done with ajaxUpdater which can’t be done with ajaxRequest? I’ve just used your ajaxRequest tutorial to create my first bit of ajax, thanks a lot for the help, very very handy. I built the ajax part in less than 20 min… without that tutorial, it would have probably taken me several hours.

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